I-to-V Amplifier - Stability
OPITOV.CIR Download the SPICE file
If you said that the easy application of a trans-impedance amp is too good to be true - you'd be right! Optimizing current-to-voltage amplifiers can be one of the most challenging aspects of op amp design. Why? The main culprit is the sensor's own capacitance CS.
Capacitance CS brings two ill effects into your circuit.
CIRCUIT INSIGHT Insert CS=100pF across IS by removing the * at the beginning of the CS statement (also make values RS=500k and RF=100k). Run a simulation and plot the Transient Response of the output V(2). What happened to the output voltage? How much overshoot and ringing does CS cause?
Now, let's see how CS puts a bump in an otherwise flat frequency response. Plot the AC Response of the output VM(2). How big is the peak in the response versus frequency?
Restoring stability requires counteracting the undesirable low-pass filter RF and CS in the feedback path from output to input. You can do this with a high-pass filter in the same feedback path. Just add capacitor CF. High-pass filter, CF and RS, adds positive phase to the loop pushing the circuit toward stability. But, as you know, circuit design is an arena of compromise. And typically, the first casualty of stability is bandwidth.
HANDS-ON DESIGN Place CF=2PF across RF by removing the * at the beginning of the CF statement. Run a simulation. Check out the Transient Response of output V(2). How much of the overshoot and ringing have been reduced? Increase CF until the overshoot and ringing are gone. But as you do this, notice what's happening to the rise time.
Take a look at the AC Response VM(2). Yes, the peak is being reduced, but, so is the overall bandwidth! That's because CF and RF create a low-pass filter in the forward signal gain path from IS to Vo.
Tuning your circuit for optimum response can be a two step process:
Download the file or copy this netlist into a text file with the *.cir extention.
OPITOV.CIR - CURRENT-TO-VOLTAGE CONVERTER (TRANSIMPEDANCE AMP) * * SENSOR IS 0 1 AC 1 PWL(0US 0UA 1US 10UA 20US 10UA 21US 0 40US 0) *RS 1 0 500K *CS 1 0 100PF * * TRANSIMPEDANCE AMPLIFIER RF 1 2 100K *CF 1 2 2PF XOP1 0 1 2 OPAMP1 * * OPAMP MACRO MODEL, SINGLE-POLE * connections: non-inverting input * | inverting input * | | output * | | | .SUBCKT OPAMP1 1 2 6 * INPUT IMPEDANCE RIN 1 2 10MEG * gain bandwidth product = DCGAIN x POLE1 = 10MHZ * DCGAIN=100K AND POLE1=100HZ EGAIN 3 0 1 2 100K R1 3 4 1K C1 4 0 1.5915UF * OUTPUT BUFFER AND RESISTANCE EBUFFER 5 0 4 0 1 ROUT 5 6 10 .ENDS * * ANALYSIS .TRAN 0.2US 40US .AC DEC 10 100 10MEG * VIEW RESULTS .PROBE .END
© 2002-2010 eCircuit Center